What are the solutions to the equation 4n^2-10n-104=0 ?

The solutions to the equation 4n^2-10n-104=0 are n= 13/2 ,n=-4

Find the zeros of 4n^2-10n-104=0

The zeros of 4n^2-10n-104=0 are n= 13/2 ,n=-4

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4 n^{2} - 10 n - 104 = 0

n = \frac{13}{2}, n = - 4

Solution steps

4 n^{2} - 10 n - 104 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 4 ( - 104 )}{2 \cdot 4}

(- 10)^{2} - 4 \cdot 4 (- 104) = 42

n_{1, 2} = \frac{- ( - 10 ) \pm 42}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 42}{2 \cdot 4}, n_{2} = \frac{- ( - 10 ) - 42}{2 \cdot 4}

n = \frac{- ( - 10 ) + 42}{2 \cdot 4} : \frac{13}{2}

n = \frac{- ( - 10 ) - 42}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

n = \frac{13}{2}, n = - 4

2 x^{2} - 12 x < - 5 x - 3

\frac{2}{x - 4} > \frac{1}{3}

\frac{4}{9} \cdot 9

4 \leq ∣ q + 6 ∣

30 = \frac{x}{3.5}

What are the solutions to the equation 4n^2-10n-104=0 ?
The solutions to the equation 4n^2-10n-104=0 are n= 13/2 ,n=-4
Find the zeros of 4n^2-10n-104=0
The zeros of 4n^2-10n-104=0 are n= 13/2 ,n=-4