What are the solutions to the equation x^2+11x-12=0 ?

The solutions to the equation x^2+11x-12=0 are x=1,x=-12

Find the zeros of x^2+11x-12=0

The zeros of x^2+11x-12=0 are x=1,x=-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 11 x - 12 = 0

x = 1, x = - 12

Solution steps

x^{2} + 11 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 12) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 1}, x_{2} = \frac{- 11 - 13}{2 \cdot 1}

x = \frac{- 11 + 13}{2 \cdot 1} : 1

x = \frac{- 11 - 13}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 1, x = - 12

∣ x + 6 ∣ = 3

3 x^{2} - 16 x - 3 = - 9 x + 3

\frac{( 2 x ^{4} y ^{0} ) ^{2}}{x ^{6}}

x^{2} + 6 x - 12 = 0

x^{3} - 3^{3}

What are the solutions to the equation x^2+11x-12=0 ?
The solutions to the equation x^2+11x-12=0 are x=1,x=-12
Find the zeros of x^2+11x-12=0
The zeros of x^2+11x-12=0 are x=1,x=-12