What are the solutions to the equation 5x^2-7x-2=0 ?

The solutions to the equation 5x^2-7x-2=0 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)

Find the zeros of 5x^2-7x-2=0

The zeros of 5x^2-7x-2=0 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)

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5 x^{2} - 7 x - 2 = 0

x = \frac{7 + 89}{10}, x = \frac{7 - 89}{10}

Decimal Notation

x = 1.64339 \dots, x = - 0.24339 \dots

Solution steps

5 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 2) = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 5}

x = \frac{- ( - 7 ) + 89}{2 \cdot 5} : \frac{7 + 89}{10}

x = \frac{- ( - 7 ) - 89}{2 \cdot 5} : \frac{7 - 89}{10}

The solutions to the quadratic equation are:

x = \frac{7 + 89}{10}, x = \frac{7 - 89}{10}

- 1.5 + 3 x = 12.5 - 4 x

x^{2} - 6 x + 1 = \frac{3 x + 5}{2}

\frac{6}{\frac{1}{2}}

(4 y + 2)^{2} = 4

\frac{7 ^{- 6}}{7 ^{- 2}}

What are the solutions to the equation 5x^2-7x-2=0 ?
The solutions to the equation 5x^2-7x-2=0 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)
Find the zeros of 5x^2-7x-2=0
The zeros of 5x^2-7x-2=0 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)