What are the solutions to the equation -16x^2+24x+16=0 ?

The solutions to the equation -16x^2+24x+16=0 are x=-1/2 ,x=2

Find the zeros of -16x^2+24x+16=0

The zeros of -16x^2+24x+16=0 are x=-1/2 ,x=2

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- 16 x^{2} + 24 x + 16 = 0

x = - \frac{1}{2}, x = 2

Decimal Notation

x = - 0.5, x = 2

Solution steps

- 16 x^{2} + 24 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 16 ) \cdot 16}{2 ( - 16 )}

2 4^{2} - 4 (- 16) \cdot 16 = 40

x_{1, 2} = \frac{- 24 \pm 40}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 24 + 40}{2 ( - 16 )}, x_{2} = \frac{- 24 - 40}{2 ( - 16 )}

x = \frac{- 24 + 40}{2 ( - 16 )} : - \frac{1}{2}

x = \frac{- 24 - 40}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = 2

(\frac{x}{y ^{\frac{1}{2}}} + \frac{y ^{\frac{1}{2}}}{x})^{5}

\frac{x + 1}{3} + \frac{x + 2}{7} = 2

\frac{2}{3} \cdot 15

r^{2} + 12 r + 27 = 0

2 (x + 4) = 12

What are the solutions to the equation -16x^2+24x+16=0 ?
The solutions to the equation -16x^2+24x+16=0 are x=-1/2 ,x=2
Find the zeros of -16x^2+24x+16=0
The zeros of -16x^2+24x+16=0 are x=-1/2 ,x=2