What is ((x+4)(x-5))/((x+6)(3x-2))>= 0 ?

The solution to ((x+4)(x-5))/((x+6)(3x-2))>= 0 is x = 5

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((x+4)(x-5))/((x+6)(3x-2))>= 0

\frac{( x + 4 ) ( x - 5 )}{( x + 6 ) ( 3 x - 2 )} \geq 0

x < - 6 or - 4 \leq x < \frac{2}{3} or x \geq 5

Interval Notation

(- \infty, - 6) \cup [- 4, \frac{2}{3}) \cup [5, \infty)

Decimal Notation

x < - 6 or - 4 \leq x < 0.66666 \dots or x \geq 5

Solution steps

\frac{( x + 4 ) ( x - 5 )}{( x + 6 ) ( 3 x - 2 )} \geq 0

Identify the intervals

x < - 6 or - 4 \leq x < \frac{2}{3} or x \geq 5

7 (x + 9) = 9 x + 5

280 = - 4. 9^{2} + 280 θ

\frac{2}{7} + \frac{4}{7}

- 2 x^{3} + 5 x^{2} + 3 x

∣ 1 - 5 a ∣ = 29

What is ((x+4)(x-5))/((x+6)(3x-2))>= 0 ?
The solution to ((x+4)(x-5))/((x+6)(3x-2))>= 0 is x<-6\lor-4<= x< 2/3 \lor x>= 5