What is the answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 ?

The answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 is x=5

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3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) + 4 = 0

x = 5

Solution steps

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) + 4 = 0

Move

4

to the right side

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) = - 4

Expand

3 x (x - 3) + 5 (x + 7) - x (x + 1) - 2 (x^{2} + 7) : - 5 x + 21

- 5 x + 21 = - 4

Move

21

to the right side

- 5 x = - 25

Divide both sides by

- 5

x = 5

\frac{7 π}{4} \cdot \frac{180}{π}

14

C + 35 < - 99

16 x^{2} + 0.5 + \frac{1}{256 x ^{2}}

\frac{5 h + 2}{6} = 7

What is the answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 ?
The answer to 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0 is x=5
Solve for x: 3x(x-3)+5(x+7)-x(x+1)-2(x^2+7)+4=0
The solution is x=5