What are the solutions to the equation (x+2)^2=16 ?

The solutions to the equation (x+2)^2=16 are x=2,x=-6

Find the zeros of (x+2)^2=16

The zeros of (x+2)^2=16 are x=2,x=-6

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(x + 2)^{2} = 16

x = 2, x = - 6

Solution steps

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

(3 - 4 i) (- 3 + 2 i)

2 (x + 1)^{2} - 6 (x + 1) + 4

5 x^{\frac{14}{5}} - 48 x^{\frac{9}{5}} + 64 x^{\frac{4}{5}}

- 15 x + 4 = 6

\frac{1}{2} + \frac{2}{3} + \frac{3}{4} + \frac{4}{5} + \frac{5}{6} + \frac{6}{7}

What are the solutions to the equation (x+2)^2=16 ?
The solutions to the equation (x+2)^2=16 are x=2,x=-6
Find the zeros of (x+2)^2=16
The zeros of (x+2)^2=16 are x=2,x=-6