What are the solutions to the equation 25t+5t^2+30=0 ?

The solutions to the equation 25t+5t^2+30=0 are t=-2,t=-3

Find the zeros of 25t+5t^2+30=0

The zeros of 25t+5t^2+30=0 are t=-2,t=-3

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25 t + 5 t^{2} + 30 = 0

t = - 2, t = - 3

Solution steps

25 t + 5 t^{2} + 30 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 t^{2} + 25 t + 30 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 5 \cdot 30}{2 \cdot 5}

2 5^{2} - 4 \cdot 5 \cdot 30 = 5

t_{1, 2} = \frac{- 25 \pm 5}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- 25 + 5}{2 \cdot 5}, t_{2} = \frac{- 25 - 5}{2 \cdot 5}

t = \frac{- 25 + 5}{2 \cdot 5} : - 2

t = \frac{- 25 - 5}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

t = - 2, t = - 3

\frac{8}{( 2 ( 2 + 2 ) )}

7^{\frac{5}{2}}

2 > - 3 t - 10

- 14 > w + 3 or 3 w \geq - 27

(22)^{2}

What are the solutions to the equation 25t+5t^2+30=0 ?
The solutions to the equation 25t+5t^2+30=0 are t=-2,t=-3
Find the zeros of 25t+5t^2+30=0
The zeros of 25t+5t^2+30=0 are t=-2,t=-3