What are the solutions to the equation y^2-5y+6=0 ?

The solutions to the equation y^2-5y+6=0 are y=3,y=2

Find the zeros of y^2-5y+6=0

The zeros of y^2-5y+6=0 are y=3,y=2

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y^{2} - 5 y + 6 = 0

y = 3, y = 2

Solution steps

y^{2} - 5 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

y_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

y = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

y = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 3, y = 2

1 + 8 x - 14 = 19

- 10 x > - 7

3 (x + 1) - 8 = 14 - 2 (3 x - 4)

\frac{18}{( 3 + 3 ) ^{3}}

- \frac{1}{6} (600)^{2} + 200 (600)

What are the solutions to the equation y^2-5y+6=0 ?
The solutions to the equation y^2-5y+6=0 are y=3,y=2
Find the zeros of y^2-5y+6=0
The zeros of y^2-5y+6=0 are y=3,y=2