What are the solutions to the equation r^2+36=0 ?

The solutions to the equation r^2+36=0 are r=6i,r=-6i

Find the zeros of r^2+36=0

The zeros of r^2+36=0 are r=6i,r=-6i

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r^{2} + 36 = 0

r = 6 i, r = - 6 i

Solution steps

r^{2} + 36 = 0

Move

36

to the right side

r^{2} = - 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 36, r = - - 36

- 36 = 6 i

- - 36 = - 6 i

r = 6 i, r = - 6 i

x^{2} + 0 x - 1 = 0

2 \cdot 72

2 (x + 4) = 30

4 x^{3} + 24 x^{2}

25 a^{2} + 30 ab + 9 b^{2}

What are the solutions to the equation r^2+36=0 ?
The solutions to the equation r^2+36=0 are r=6i,r=-6i
Find the zeros of r^2+36=0
The zeros of r^2+36=0 are r=6i,r=-6i