What are the solutions to the equation 40= 1/2 (x)(2x+6) ?

The solutions to the equation 40= 1/2 (x)(2x+6) are x=5,x=-8

Find the zeros of 40= 1/2 (x)(2x+6)

The zeros of 40= 1/2 (x)(2x+6) are x=5,x=-8

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40 = \frac{1}{2} (x) (2 x + 6)

x = 5, x = - 8

Solution steps

40 = \frac{1}{2} (x) (2 x + 6)

Multiply both sides by

2

80 = x (2 x + 6)

Expand

x (2 x + 6) : 2 x^{2} + 6 x

80 = 2 x^{2} + 6 x

Switch sides

2 x^{2} + 6 x = 80

Move

80

to the left side

2 x^{2} + 6 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 80 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 80) = 26

x_{1, 2} = \frac{- 6 \pm 26}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 26}{2 \cdot 2}, x_{2} = \frac{- 6 - 26}{2 \cdot 2}

x = \frac{- 6 + 26}{2 \cdot 2} : 5

x = \frac{- 6 - 26}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = 5, x = - 8

(2 x - 1) 2 = 18

x^{5} + 3 x^{4} - 9 x^{3} - 31 x^{2} + 36

(1 + \frac{2}{7}) \cdot \frac{2}{3}

∣ y ∣ < 3

4 x^{2} + 5 x + 2 = 2 x^{2} + 7 x - 1

What are the solutions to the equation 40= 1/2 (x)(2x+6) ?
The solutions to the equation 40= 1/2 (x)(2x+6) are x=5,x=-8
Find the zeros of 40= 1/2 (x)(2x+6)
The zeros of 40= 1/2 (x)(2x+6) are x=5,x=-8