What is factor 6y^2-5y-4 ?

The solution to factor 6y^2-5y-4 is (2y+1)(3y-4)

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factor 6y^2-5y-4

factor

6 y^{2} - 5 y - 4

(2 y + 1) (3 y - 4)

Solution steps

6 y^{2} - 5 y - 4

Break the expression into groups

= (6 y^{2} + 3 y) + (- 8 y - 4)

Factor out

3 y

from

6 y^{2} + 3 y : 3 y (2 y + 1)

Factor out

- 4

from

- 8 y - 4 : - 4 (2 y + 1)

= 3 y (2 y + 1) - 4 (2 y + 1)

Factor out common term

2 y + 1

= (2 y + 1) (3 y - 4)

lo g_{14} (2) + lo g_{14} (7)

(x^{7})^{2}

\frac{1}{8} (- \frac{4}{5})

3 x^{2} - 9 x + 15

\frac{x ^{2} ( 8 + x ) ( x - 8 )}{( x + 5 ) ( x - 2 )} \geq 0