What is factor 2y^2+9y-5 ?

The solution to factor 2y^2+9y-5 is (2y-1)(y+5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 2y^2+9y-5

factor

2 y^{2} + 9 y - 5

(2 y - 1) (y + 5)

Solution steps

2 y^{2} + 9 y - 5

Break the expression into groups

= (2 y^{2} - y) + (10 y - 5)

Factor out

y

from

2 y^{2} - y : y (2 y - 1)

Factor out

5

from

10 y - 5 : 5 (2 y - 1)

= y (2 y - 1) + 5 (2 y - 1)

Factor out common term

2 y - 1

= (2 y - 1) (y + 5)

\frac{8.1 \cdot 1 0 ^{4}}{1.8 \cdot 1 0 ^{- 4}}

225 x^{2} - 289 y^{2}

(- 16)^{\frac{3}{2}}

x^{3} - 8 x^{2} + 9 x + 18

5 x^{2} - 4 x - 12