What are the solutions to the equation 3x^2+16x=-5 ?

The solutions to the equation 3x^2+16x=-5 are x=-1/3 ,x=-5

Find the zeros of 3x^2+16x=-5

The zeros of 3x^2+16x=-5 are x=-1/3 ,x=-5

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3 x^{2} + 16 x = - 5

x = - \frac{1}{3}, x = - 5

Solution steps

3 x^{2} + 16 x = - 5

Move

5

to the left side

3 x^{2} + 16 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 \cdot 5 = 14

x_{1, 2} = \frac{- 16 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 16 + 14}{2 \cdot 3}, x_{2} = \frac{- 16 - 14}{2 \cdot 3}

x = \frac{- 16 + 14}{2 \cdot 3} : - \frac{1}{3}

x = \frac{- 16 - 14}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - 5

4 n^{2} + 36 n - 40

5 (x - 1) - 6 x \geq - 3

4 + 3 b > 10

m^{2} - m - 42

- x^{2} - 10 x - 16

What are the solutions to the equation 3x^2+16x=-5 ?
The solutions to the equation 3x^2+16x=-5 are x=-1/3 ,x=-5
Find the zeros of 3x^2+16x=-5
The zeros of 3x^2+16x=-5 are x=-1/3 ,x=-5