What are the solutions to the equation c^2-16c+64=50 ?

The solutions to the equation c^2-16c+64=50 are c=8+5sqrt(2),c=8-5sqrt(2)

Find the zeros of c^2-16c+64=50

The zeros of c^2-16c+64=50 are c=8+5sqrt(2),c=8-5sqrt(2)

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c^{2} - 16 c + 64 = 50

c = 8 + 52, c = 8 - 52

Decimal Notation

c = 15.07106 \dots, c = 0.92893 \dots

Solution steps

c^{2} - 16 c + 64 = 50

Move

50

to the left side

c^{2} - 16 c + 14 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 14 = 102

c_{1, 2} = \frac{- ( - 16 ) \pm 10 2}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 16 ) + 10 2}{2 \cdot 1}, c_{2} = \frac{- ( - 16 ) - 10 2}{2 \cdot 1}

c = \frac{- ( - 16 ) + 10 2}{2 \cdot 1} : 8 + 52

c = \frac{- ( - 16 ) - 10 2}{2 \cdot 1} : 8 - 52

The solutions to the quadratic equation are:

c = 8 + 52, c = 8 - 52

4 m = 12

- 2 (- 3 x) (- 2 y + 1) - (- y) (4 - 5 x)

- n - 24 = 5 - n

49 - 42 b + 9 b^{2}

7 x = x + 30

What are the solutions to the equation c^2-16c+64=50 ?
The solutions to the equation c^2-16c+64=50 are c=8+5sqrt(2),c=8-5sqrt(2)
Find the zeros of c^2-16c+64=50
The zeros of c^2-16c+64=50 are c=8+5sqrt(2),c=8-5sqrt(2)