What are the solutions to the equation -x^2+4x-5=0 ?

The solutions to the equation -x^2+4x-5=0 are x=2-i,x=2+i

Find the zeros of -x^2+4x-5=0

The zeros of -x^2+4x-5=0 are x=2-i,x=2+i

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- x^{2} + 4 x - 5 = 0

x = 2 - i, x = 2 + i

Solution steps

- x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) (- 5) : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 i}{2 ( - 1 )}

x = \frac{- 4 + 2 i}{2 ( - 1 )} : 2 - i

x = \frac{- 4 - 2 i}{2 ( - 1 )} : 2 + i

The solutions to the quadratic equation are:

x = 2 - i, x = 2 + i

3 x^{3} - 6 x^{2} - 4 x + 8

36 x^{2} - 4 y^{2}

3 x^{2} = 375

(- \frac{w ^{3}}{6})^{- 2}

- 2 ∣ 6 x ∣ + 9 < 1

What are the solutions to the equation -x^2+4x-5=0 ?
The solutions to the equation -x^2+4x-5=0 are x=2-i,x=2+i
Find the zeros of -x^2+4x-5=0
The zeros of -x^2+4x-5=0 are x=2-i,x=2+i