What is (4n+24)/(n^2-2n-48) ?

The solution to (4n+24)/(n^2-2n-48) is 4/(n-8)

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simplify (4n+24)/(n^2-2n-48)

simplify

\frac{4 n + 24}{n ^{2} - 2 n - 48}

\frac{4}{n - 8}

Solution steps

\frac{4 n + 24}{n ^{2} - 2 n - 48}

Factor

4 n + 24 : 4 (n + 6)

= \frac{4 ( n + 6 )}{n ^{2} - 2 n - 48}

Factor

n^{2} - 2 n - 48 : (n + 6) (n - 8)

= \frac{4 ( n + 6 )}{( n + 6 ) ( n - 8 )}

Cancel the common factor:

n + 6

= \frac{4}{n - 8}

y^{4} (y + 2)^{3} + y^{5} (y + 2)^{4}

\frac{2}{5} \cdot \frac{5}{2}

- 12 x < 36

6 x - 5 > - 29

18 y^{3} x^{2} - 3 x y^{4}