What are the solutions to the equation x^2-24x+128=0 ?

The solutions to the equation x^2-24x+128=0 are x=16,x=8

Find the zeros of x^2-24x+128=0

The zeros of x^2-24x+128=0 are x=16,x=8

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x^{2} - 24 x + 128 = 0

x = 16, x = 8

Solution steps

x^{2} - 24 x + 128 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 128}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 128 = 8

x_{1, 2} = \frac{- ( - 24 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 8}{2 \cdot 1}

x = \frac{- ( - 24 ) + 8}{2 \cdot 1} : 16

x = \frac{- ( - 24 ) - 8}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

x = 16, x = 8

x^{2} - 18 x + 5 = 0

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6 b^{2} - b - 35

\frac{8 x ^{3} + 22 x ^{2} + 7 x - 10}{2 x ^{2} + 9 x + 9} \geq 0

What are the solutions to the equation x^2-24x+128=0 ?
The solutions to the equation x^2-24x+128=0 are x=16,x=8
Find the zeros of x^2-24x+128=0
The zeros of x^2-24x+128=0 are x=16,x=8