What are the solutions to the equation 7.0795t=57.34t-16.1t^2 ?

The solutions to the equation 7.0795t=57.34t-16.1t^2 are t=0,t=(100.521)/(32.2)

Find the zeros of 7.0795t=57.34t-16.1t^2

The zeros of 7.0795t=57.34t-16.1t^2 are t=0,t=(100.521)/(32.2)

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7.0795 t = 57.34 t - 16.1 t^{2}

t = 0, t = \frac{100.521}{32.2}

Decimal Notation

t = 0, t = 3.12177 \dots

Solution steps

7.0795 t = 57.34 t - 16.1 t^{2}

Switch sides

57.34 t - 16.1 t^{2} = 7.0795 t

Move

7.0795 t

to the left side

- 16.1 t^{2} + 50.2605 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 50.2605 \pm 50.260 5 ^{2} - 4 ( - 16.1 ) \cdot 0}{2 ( - 16.1 )}

50.260 5^{2} - 4 (- 16.1) \cdot 0 = 50.2605

t_{1, 2} = \frac{- 50.2605 \pm 50.2605}{2 ( - 16.1 )}

Separate the solutions

t_{1} = \frac{- 50.2605 + 50.2605}{2 ( - 16.1 )}, t_{2} = \frac{- 50.2605 - 50.2605}{2 ( - 16.1 )}

t = \frac{- 50.2605 + 50.2605}{2 ( - 16.1 )} : 0

t = \frac{- 50.2605 - 50.2605}{2 ( - 16.1 )} : \frac{100.521}{32.2}

The solutions to the quadratic equation are:

t = 0, t = \frac{100.521}{32.2}

\frac{x}{2} \geq \frac{9}{x + 1} + 8

3 x + 4 \leq 6 - x

- 3 x > 12

2 x^{2} + 5 x < x^{2} + 1

1^{\frac{3}{5}}

What are the solutions to the equation 7.0795t=57.34t-16.1t^2 ?
The solutions to the equation 7.0795t=57.34t-16.1t^2 are t=0,t=(100.521)/(32.2)
Find the zeros of 7.0795t=57.34t-16.1t^2
The zeros of 7.0795t=57.34t-16.1t^2 are t=0,t=(100.521)/(32.2)