What are the solutions to the equation 3x^2+3=7x ?

The solutions to the equation 3x^2+3=7x are x=(7+sqrt(13))/6 ,x=(7-sqrt(13))/6

Find the zeros of 3x^2+3=7x

The zeros of 3x^2+3=7x are x=(7+sqrt(13))/6 ,x=(7-sqrt(13))/6

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3 x^{2} + 3 = 7 x

x = \frac{7 + 13}{6}, x = \frac{7 - 13}{6}

Decimal Notation

x = 1.76759 \dots, x = 0.56574 \dots

Solution steps

3 x^{2} + 3 = 7 x

Move

7 x

to the left side

3 x^{2} + 3 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 3 = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 3}

x = \frac{- ( - 7 ) + 13}{2 \cdot 3} : \frac{7 + 13}{6}

x = \frac{- ( - 7 ) - 13}{2 \cdot 3} : \frac{7 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{7 + 13}{6}, x = \frac{7 - 13}{6}

40 (\frac{π}{180})

\frac{- 6 x + 78}{5} = 4 x

4 m^{2} + 18 m - 10

\frac{x}{- 3} = 2

14 x + 2 > - 26

What are the solutions to the equation 3x^2+3=7x ?
The solutions to the equation 3x^2+3=7x are x=(7+sqrt(13))/6 ,x=(7-sqrt(13))/6
Find the zeros of 3x^2+3=7x
The zeros of 3x^2+3=7x are x=(7+sqrt(13))/6 ,x=(7-sqrt(13))/6