What is factor (w+4)^3-(w+4)^2(w+1) ?

The solution to factor (w+4)^3-(w+4)^2(w+1) is 3(w+4)^2

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factor (w+4)^3-(w+4)^2(w+1)

factor

(w + 4)^{3} - (w + 4)^{2} (w + 1)

3 (w + 4)^{2}

Solution steps

(w + 4)^{3} - (w + 4)^{2} (w + 1)

Factor out common term

(w + 4)^{2} : (w + 4)^{2} (w + 4 - (w + 1))

= (w + 4)^{2} (w + 4 - (w + 1))

Expand

w + 4 - (w + 1) : 3

= (w + 4)^{2} \cdot 3

= 3 (w + 4)^{2}

T = 2 π \frac{2}{32}

- x^{2} - 10 x + 11 < - 2 x^{2} - 2 x - 1

a \cdot b

6 4^{\frac{- 1}{2}}

4 (a + b)^{2} + 7 (a + b) - 2

What is factor (w+4)^3-(w+4)^2(w+1) ?
The solution to factor (w+4)^3-(w+4)^2(w+1) is 3(w+4)^2