What are the solutions to the equation 6b^2+4=-56 ?

The solutions to the equation 6b^2+4=-56 are b=sqrt(10)i,b=-sqrt(10)i

Find the zeros of 6b^2+4=-56

The zeros of 6b^2+4=-56 are b=sqrt(10)i,b=-sqrt(10)i

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6 b^{2} + 4 = - 56

b = 10 i, b = - 10 i

Solution steps

6 b^{2} + 4 = - 56

Move

4

to the right side

6 b^{2} = - 60

Divide both sides by

6

b^{2} = - 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = - 10, b = - - 10

- 10 = 10 i

- - 10 = - 10 i

b = 10 i, b = - 10 i

45 x^{2} - 20 m^{2}

3^{\frac{1}{2} - 1}

(\frac{2}{3})^{- 1}

\frac{3}{u ^{\frac{5}{2}} v ^{\frac{1}{2}}}

3 + 12 (3 p + 2) = 9 (p - 3)

What are the solutions to the equation 6b^2+4=-56 ?
The solutions to the equation 6b^2+4=-56 are b=sqrt(10)i,b=-sqrt(10)i
Find the zeros of 6b^2+4=-56
The zeros of 6b^2+4=-56 are b=sqrt(10)i,b=-sqrt(10)i