What are the solutions to the equation -10x^2+13x=4 ?

The solutions to the equation -10x^2+13x=4 are x= 1/2 ,x= 4/5

Find the zeros of -10x^2+13x=4

The zeros of -10x^2+13x=4 are x= 1/2 ,x= 4/5

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- 10 x^{2} + 13 x = 4

x = \frac{1}{2}, x = \frac{4}{5}

Decimal Notation

x = 0.5, x = 0.8

Solution steps

- 10 x^{2} + 13 x = 4

Move

4

to the left side

- 10 x^{2} + 13 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 ( - 10 ) ( - 4 )}{2 ( - 10 )}

1 3^{2} - 4 (- 10) (- 4) = 3

x_{1, 2} = \frac{- 13 \pm 3}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 13 + 3}{2 ( - 10 )}, x_{2} = \frac{- 13 - 3}{2 ( - 10 )}

x = \frac{- 13 + 3}{2 ( - 10 )} : \frac{1}{2}

x = \frac{- 13 - 3}{2 ( - 10 )} : \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = \frac{4}{5}

20 > 8 x + 4

(\frac{7}{3})^{5}

r^{2} + 7 = 0

5 a^{2} - 10 a + 5

\frac{m n ^{3}}{n ^{2}}

What are the solutions to the equation -10x^2+13x=4 ?
The solutions to the equation -10x^2+13x=4 are x= 1/2 ,x= 4/5
Find the zeros of -10x^2+13x=4
The zeros of -10x^2+13x=4 are x= 1/2 ,x= 4/5