What are the solutions to the equation 288=-16t^2+144t ?

The solutions to the equation 288=-16t^2+144t are t=3,t=6

Find the zeros of 288=-16t^2+144t

The zeros of 288=-16t^2+144t are t=3,t=6

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288 = - 16 t^{2} + 144 t

t = 3, t = 6

Solution steps

288 = - 16 t^{2} + 144 t

Switch sides

- 16 t^{2} + 144 t = 288

Move

288

to the left side

- 16 t^{2} + 144 t - 288 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 ( - 16 ) ( - 288 )}{2 ( - 16 )}

14 4^{2} - 4 (- 16) (- 288) = 48

t_{1, 2} = \frac{- 144 \pm 48}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 144 + 48}{2 ( - 16 )}, t_{2} = \frac{- 144 - 48}{2 ( - 16 )}

t = \frac{- 144 + 48}{2 ( - 16 )} : 3

t = \frac{- 144 - 48}{2 ( - 16 )} : 6

The solutions to the quadratic equation are:

t = 3, t = 6

(x + 2)^{2} = - 81

(x - 7) = 10

\frac{4}{3} + \frac{1}{2}

- 4 216 x^{2} y^{2} z

\frac{6 - i}{5}

What are the solutions to the equation 288=-16t^2+144t ?
The solutions to the equation 288=-16t^2+144t are t=3,t=6
Find the zeros of 288=-16t^2+144t
The zeros of 288=-16t^2+144t are t=3,t=6