What are the solutions to the equation y^2+8y+25=0 ?

The solutions to the equation y^2+8y+25=0 are y=-4+3i,y=-4-3i

Find the zeros of y^2+8y+25=0

The zeros of y^2+8y+25=0 are y=-4+3i,y=-4-3i

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y^{2} + 8 y + 25 = 0

y = - 4 + 3 i, y = - 4 - 3 i

Solution steps

y^{2} + 8 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 25 : 6 i

y_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 6 i}{2 \cdot 1}, y_{2} = \frac{- 8 - 6 i}{2 \cdot 1}

y = \frac{- 8 + 6 i}{2 \cdot 1} : - 4 + 3 i

y = \frac{- 8 - 6 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

y = - 4 + 3 i, y = - 4 - 3 i

5 n - 12 n = - 84

\frac{3}{4} - \frac{5}{9}

- 9 \leq - 2 + \frac{q}{3}

\frac{10 !}{2 ! \cdot 8 !}

What are the solutions to the equation y^2+8y+25=0 ?
The solutions to the equation y^2+8y+25=0 are y=-4+3i,y=-4-3i
Find the zeros of y^2+8y+25=0
The zeros of y^2+8y+25=0 are y=-4+3i,y=-4-3i