What are the solutions to the equation s^2+9s+20=0 ?

The solutions to the equation s^2+9s+20=0 are s=-4,s=-5

Find the zeros of s^2+9s+20=0

The zeros of s^2+9s+20=0 are s=-4,s=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} + 9 s + 20 = 0

s = - 4, s = - 5

Solution steps

s^{2} + 9 s + 20 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

s_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 9 + 1}{2 \cdot 1}, s_{2} = \frac{- 9 - 1}{2 \cdot 1}

s = \frac{- 9 + 1}{2 \cdot 1} : - 4

s = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

s = - 4, s = - 5

- 2 x + 6 = 0

- 7 x > 42

0.00000032 \geq \frac{1}{n ^{4}}

1 - 2 (\frac{3}{5})^{2}

(\frac{3 ^{4} \cdot 3 ^{2}}{3 ^{5}})^{- 3}

What are the solutions to the equation s^2+9s+20=0 ?
The solutions to the equation s^2+9s+20=0 are s=-4,s=-5
Find the zeros of s^2+9s+20=0
The zeros of s^2+9s+20=0 are s=-4,s=-5