What are the solutions to the equation r^2+7r=0 ?

The solutions to the equation r^2+7r=0 are r=0,r=-7

Find the zeros of r^2+7r=0

The zeros of r^2+7r=0 are r=0,r=-7

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r^{2} + 7 r = 0

r = 0, r = - 7

Solution steps

r^{2} + 7 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

r_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 7 + 7}{2 \cdot 1}, r_{2} = \frac{- 7 - 7}{2 \cdot 1}

r = \frac{- 7 + 7}{2 \cdot 1} : 0

r = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

r = 0, r = - 7

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m^{2} - 8 mn + 7 n^{2}

\frac{6}{7} \cdot (\frac{9}{4} + \frac{3}{8})

\frac{1}{4} - \frac{4}{5}

What are the solutions to the equation r^2+7r=0 ?
The solutions to the equation r^2+7r=0 are r=0,r=-7
Find the zeros of r^2+7r=0
The zeros of r^2+7r=0 are r=0,r=-7