What are the solutions to the equation x^2-12x+18=0 ?

The solutions to the equation x^2-12x+18=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))

Find the zeros of x^2-12x+18=0

The zeros of x^2-12x+18=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))

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x^{2} - 12 x + 18 = 0

x = 3 (2 + 2), x = 3 (2 - 2)

Decimal Notation

x = 10.24264 \dots, x = 1.75735 \dots

Solution steps

x^{2} - 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 18 = 62

x_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 2}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 6 2}{2 \cdot 1}

x = \frac{- ( - 12 ) + 6 2}{2 \cdot 1} : 3 (2 + 2)

x = \frac{- ( - 12 ) - 6 2}{2 \cdot 1} : 3 (2 - 2)

The solutions to the quadratic equation are:

x = 3 (2 + 2), x = 3 (2 - 2)

x^{3} + 7 x^{2} - 5 x - 35

- 5 x > 25

3 (y - 6)^{2} = 48

\frac{( 1 )}{( 9 )} x^{2} - \frac{( 1 )}{( 3 )} x + \frac{( 1 )}{( 4 )} = 0

2 y^{2} + y - 4 = 0

What are the solutions to the equation x^2-12x+18=0 ?
The solutions to the equation x^2-12x+18=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))
Find the zeros of x^2-12x+18=0
The zeros of x^2-12x+18=0 are x=3(2+sqrt(2)),x=3(2-sqrt(2))