What are the solutions to the equation (x+3)^2=-1 ?

The solutions to the equation (x+3)^2=-1 are x=i-3,x=-i-3

Find the zeros of (x+3)^2=-1

The zeros of (x+3)^2=-1 are x=i-3,x=-i-3

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(x + 3)^{2} = - 1

x = i - 3, x = - i - 3

Solution steps

(x + 3)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 1 : x = i - 3

Solve

x + 3 = - - 1 : x = - i - 3

The solutions to the quadratic equation are:

x = i - 3, x = - i - 3

- 27

\frac{1}{2} \cdot 4

(2 x^{2})^{4}

8 - 3 m = 26

k^{2} + 9 k + 14

What are the solutions to the equation (x+3)^2=-1 ?
The solutions to the equation (x+3)^2=-1 are x=i-3,x=-i-3
Find the zeros of (x+3)^2=-1
The zeros of (x+3)^2=-1 are x=i-3,x=-i-3