What are the solutions to the equation (x(x-3))/6-x/2 =0 ?

The solutions to the equation (x(x-3))/6-x/2 =0 are x=6,x=0

Find the zeros of (x(x-3))/6-x/2 =0

The zeros of (x(x-3))/6-x/2 =0 are x=6,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{x ( x - 3 )}{6} - \frac{x}{2} = 0

x = 6, x = 0

Solution steps

\frac{x ( x - 3 )}{6} - \frac{x}{2} = 0

Find Least Common Multiplier of

6, 2 : 6

Multiply by LCM=

6

\frac{x ( x - 3 )}{6} \cdot 6 - \frac{x}{2} \cdot 6 = 0 \cdot 6

Simplify

x (x - 3) - 3 x = 0

Expand

x (x - 3) - 3 x : x^{2} - 6 x

x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

x = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 6, x = 0

\frac{6 !}{4 ! \cdot ( 6 - 4 ) !}

2 x + 4 = 20

\frac{x - 6}{x + 2} > 0

- 1 < \frac{a + 72}{6} < 5

4 x + 1 > 9 or 3 x + 3 \leq - 6

What are the solutions to the equation (x(x-3))/6-x/2 =0 ?
The solutions to the equation (x(x-3))/6-x/2 =0 are x=6,x=0
Find the zeros of (x(x-3))/6-x/2 =0
The zeros of (x(x-3))/6-x/2 =0 are x=6,x=0