What is factor 9u^2+42u+49 ?

The solution to factor 9u^2+42u+49 is (3u+7)^2

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factor 9u^2+42u+49

factor

9 u^{2} + 42 u + 49

(3 u + 7)^{2}

Solution steps

9 u^{2} + 42 u + 49

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

9 u^{2} = (3 u)^{2}

49 = 7^{2}

42 u = 2 \cdot 3 u \cdot 7

= (3 u)^{2} + 2 \cdot 3 u \cdot 7 + 7^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(3 u)^{2} + 2 \cdot 3 u \cdot 7 + 7^{2} = (3 u + 7)^{2}

= (3 u + 7)^{2}

14 x - (7 x + 5) = 7 x + 8

4 - 2 x \leq 3 x - 1

\frac{x ^{- 8}}{x ^{4} y ^{4} y ^{- 3}}

- \frac{2}{3} - 5

2 x^{2} + 4 x + 3 = 0