What are the solutions to the equation (5x-1)^2=7 ?

The solutions to the equation (5x-1)^2=7 are x=(sqrt(7)+1)/5 ,x=(-sqrt(7)+1)/5

Find the zeros of (5x-1)^2=7

The zeros of (5x-1)^2=7 are x=(sqrt(7)+1)/5 ,x=(-sqrt(7)+1)/5

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(5 x - 1)^{2} = 7

x = \frac{7 + 1}{5}, x = \frac{- 7 + 1}{5}

Decimal Notation

x = 0.72915 \dots, x = - 0.32915 \dots

Solution steps

(5 x - 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 1 = 7 : x = \frac{7 + 1}{5}

Solve

5 x - 1 = - 7 : x = \frac{- 7 + 1}{5}

The solutions to the quadratic equation are:

x = \frac{7 + 1}{5}, x = \frac{- 7 + 1}{5}

7 x^{2} - 4 x y + 8 y^{2} - 11 x^{2} + 7 x y - 10 y^{2}

x^{2} + 12 x + 36 = 25

\frac{9 + 4 i}{- 8 - 8 i}

\frac{5}{2} \cdot 2

5 x^{2} + 15 x - 140 = 0

What are the solutions to the equation (5x-1)^2=7 ?
The solutions to the equation (5x-1)^2=7 are x=(sqrt(7)+1)/5 ,x=(-sqrt(7)+1)/5
Find the zeros of (5x-1)^2=7
The zeros of (5x-1)^2=7 are x=(sqrt(7)+1)/5 ,x=(-sqrt(7)+1)/5