What are the solutions to the equation (x+4)(x-9)=4x ?

The solutions to the equation (x+4)(x-9)=4x are x=12,x=-3

Find the zeros of (x+4)(x-9)=4x

The zeros of (x+4)(x-9)=4x are x=12,x=-3

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(x + 4) (x - 9) = 4 x

x = 12, x = - 3

Solution steps

(x + 4) (x - 9) = 4 x

Expand

(x + 4) (x - 9) : x^{2} - 5 x - 36

x^{2} - 5 x - 36 = 4 x

Move

4 x

to the left side

x^{2} - 9 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 36) = 15

x_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 1}

x = \frac{- ( - 9 ) + 15}{2 \cdot 1} : 12

x = \frac{- ( - 9 ) - 15}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 12, x = - 3

x^{2} = \frac{7}{9} x

\frac{3 π}{4} (\frac{180}{π})

28 = 10 a - 5 a - 2

5 x^{2} - 18 x + 9

4 (m - 2) = 24

What are the solutions to the equation (x+4)(x-9)=4x ?
The solutions to the equation (x+4)(x-9)=4x are x=12,x=-3
Find the zeros of (x+4)(x-9)=4x
The zeros of (x+4)(x-9)=4x are x=12,x=-3