What is 50+(N-40)/4 50^of ?

The solution to 50+(N-40)/4 50^of is 50+(N-40)*2^{o-2}*25^of

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simplify 50+(N-40)/4 50^of

simplify

50 + \frac{N - 40}{4} 5 0^{o} f

50 + (N - 40) \cdot 2^{o - 2} \cdot 2 5^{o} f

Solution steps

50 + \frac{N - 40}{4} \cdot 5 0^{o} f

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{N - 40}{4} \cdot 5 0^{o} f = \frac{( N - 40 ) \cdot 5 0 ^{o} f}{4}

= 50 + \frac{( N - 40 ) \cdot 5 0 ^{o} f}{4}

Factor

5 0^{o} : 2^{o} \cdot 2 5^{o}

= 50 + \frac{( N - 40 ) \cdot 2 ^{o} \cdot 2 5 ^{o} f}{4}

Factor the number:

4 = 2^{2}

= 50 + \frac{( N - 40 ) \cdot 2 ^{o} \cdot 2 5 ^{o} f}{2 ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{o}}{2 ^{2}} = 2^{o - 2}

= 50 + (N - 40) \cdot 2^{o - 2} \cdot 2 5^{o} f

z^{2} - 9

5 y - y^{2} = 6

2 x - 5 > 3

r^{2} + 49 = 0

36 - x^{2}

What is 50+(N-40)/4 50^of ?
The solution to 50+(N-40)/4 50^of is 50+(N-40)*2^{o-2}*25^of