What are the solutions to the equation x^2+1=3x ?

The solutions to the equation x^2+1=3x are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

Find the zeros of x^2+1=3x

The zeros of x^2+1=3x are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

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x^{2} + 1 = 3 x

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Decimal Notation

x = 2.61803 \dots, x = 0.38196 \dots

Solution steps

x^{2} + 1 = 3 x

Move

3 x

to the left side

x^{2} + 1 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 1 = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : \frac{3 + 5}{2}

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : \frac{3 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

5 x^{2} + 22 x \leq 15

(x^{- 1} + y^{- 1})^{- 1}

1 8^{2} = 12 (12 + x)

ln (0.99)

- \frac{186}{200} + 0.3

What are the solutions to the equation x^2+1=3x ?
The solutions to the equation x^2+1=3x are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2
Find the zeros of x^2+1=3x
The zeros of x^2+1=3x are x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2