What are the solutions to the equation x(x+8)-3=8x+1 ?

The solutions to the equation x(x+8)-3=8x+1 are x=2,x=-2

Find the zeros of x(x+8)-3=8x+1

The zeros of x(x+8)-3=8x+1 are x=2,x=-2

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x (x + 8) - 3 = 8 x + 1

x = 2, x = - 2

Solution steps

x (x + 8) - 3 = 8 x + 1

Expand

x (x + 8) - 3 : x^{2} + 8 x - 3

x^{2} + 8 x - 3 = 8 x + 1

Move

3

to the right side

x^{2} + 8 x = 8 x + 4

Move

8 x

to the left side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x y \cdot 4 x y

4 x - 1 = 5 x - 10

a x - b x + a y - b y

\frac{x ^{7}}{x ^{7}}

(\frac{2}{5}) (\frac{3}{4}) (\frac{1}{3})

What are the solutions to the equation x(x+8)-3=8x+1 ?
The solutions to the equation x(x+8)-3=8x+1 are x=2,x=-2
Find the zeros of x(x+8)-3=8x+1
The zeros of x(x+8)-3=8x+1 are x=2,x=-2