What is the answer to (6x-7)/4+(3x-5)/7 =(5x+78)/(28) ?

The answer to (6x-7)/4+(3x-5)/7 =(5x+78)/(28) is x=3

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(6x-7)/4+(3x-5)/7 =(5x+78)/(28)

\frac{6 x - 7}{4} + \frac{3 x - 5}{7} = \frac{5 x + 78}{28}

x = 3

Solution steps

\frac{6 x - 7}{4} + \frac{3 x - 5}{7} = \frac{5 x + 78}{28}

Multiply by LCM

7 (6 x - 7) + 4 (3 x - 5) = 5 x + 78

Expand

7 (6 x - 7) + 4 (3 x - 5) : 54 x - 69

54 x - 69 = 5 x + 78

Move

69

to the right side

54 x = 5 x + 147

Move

5 x

to the left side

49 x = 147

Divide both sides by

49

x = 3

- \frac{x - 1}{3} + \frac{1}{5} \leq \frac{2 x + 1}{2} - 3

x^{2} y^{2} - 144

6 4^{- \frac{1}{6}}

\frac{1}{8 i}

c^{2} + 3 c + 2 c + 6

What is the answer to (6x-7)/4+(3x-5)/7 =(5x+78)/(28) ?
The answer to (6x-7)/4+(3x-5)/7 =(5x+78)/(28) is x=3
Solve for x: (6x-7)/4+(3x-5)/7 =(5x+78)/(28)
The solution is x=3