What is 1/(2x-1)> 1/(x+2) ?

The solution to 1/(2x-1)> 1/(x+2) is x<-2\lor 1/2 <x<3

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1/(2x-1)> 1/(x+2)

\frac{1}{2 x - 1} > \frac{1}{x + 2}

x < - 2 or \frac{1}{2} < x < 3

Interval Notation

(- \infty, - 2) \cup (\frac{1}{2}, 3)

Decimal Notation

x < - 2 or 0.5 < x < 3

Solution steps

\frac{1}{2 x - 1} > \frac{1}{x + 2}

Rewrite in standard form

\frac{- x + 3}{( x + 2 ) ( 2 x - 1 )} > 0

Identify the intervals

x < - 2 or \frac{1}{2} < x < 3

1000 = \frac{k}{16}

lo g_{e} (1 + h)

- \frac{x ^{2} + 2 y ^{2}}{4 x y - y ^{2}}

∣ 3 x - 4 ∣ \leq 8

5 x \leq \frac{4 x + 2}{2} < x

What is 1/(2x-1)> 1/(x+2) ?
The solution to 1/(2x-1)> 1/(x+2) is x<-2\lor 1/2 <x<3