What are the solutions to the equation -13x^2+9x-3=0 ?

The solutions to the equation -13x^2+9x-3=0 are x= 9/26-i(5sqrt(3))/(26),x= 9/26+i(5sqrt(3))/(26)

Find the zeros of -13x^2+9x-3=0

The zeros of -13x^2+9x-3=0 are x= 9/26-i(5sqrt(3))/(26),x= 9/26+i(5sqrt(3))/(26)

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- 13 x^{2} + 9 x - 3 = 0

x = \frac{9}{26} - i \frac{5 3}{26}, x = \frac{9}{26} + i \frac{5 3}{26}

Solution steps

- 13 x^{2} + 9 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 13 ) ( - 3 )}{2 ( - 13 )}

Simplify

9^{2} - 4 (- 13) (- 3) : 53 i

x_{1, 2} = \frac{- 9 \pm 5 3 i}{2 ( - 13 )}

Separate the solutions

x_{1} = \frac{- 9 + 5 3 i}{2 ( - 13 )}, x_{2} = \frac{- 9 - 5 3 i}{2 ( - 13 )}

x = \frac{- 9 + 5 3 i}{2 ( - 13 )} : \frac{9}{26} - i \frac{5 3}{26}

x = \frac{- 9 - 5 3 i}{2 ( - 13 )} : \frac{9}{26} + i \frac{5 3}{26}

The solutions to the quadratic equation are:

x = \frac{9}{26} - i \frac{5 3}{26}, x = \frac{9}{26} + i \frac{5 3}{26}

30 \cdot 5

3 (2 x - 7) = 5 - (1 - x)

0 \leq 2

- 99 - 2 x = 48 + 5 x

y^{2} - 26 y + 29 = 0

What are the solutions to the equation -13x^2+9x-3=0 ?
The solutions to the equation -13x^2+9x-3=0 are x= 9/26-i(5sqrt(3))/(26),x= 9/26+i(5sqrt(3))/(26)
Find the zeros of -13x^2+9x-3=0
The zeros of -13x^2+9x-3=0 are x= 9/26-i(5sqrt(3))/(26),x= 9/26+i(5sqrt(3))/(26)