What are the solutions to the equation y^2-8y+25=0 ?

The solutions to the equation y^2-8y+25=0 are y=4+3i,y=4-3i

Find the zeros of y^2-8y+25=0

The zeros of y^2-8y+25=0 are y=4+3i,y=4-3i

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y^{2} - 8 y + 25 = 0

y = 4 + 3 i, y = 4 - 3 i

Solution steps

y^{2} - 8 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 25 : 6 i

y_{1, 2} = \frac{- ( - 8 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 6 i}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 6 i}{2 \cdot 1}

y = \frac{- ( - 8 ) + 6 i}{2 \cdot 1} : 4 + 3 i

y = \frac{- ( - 8 ) - 6 i}{2 \cdot 1} : 4 - 3 i

The solutions to the quadratic equation are:

y = 4 + 3 i, y = 4 - 3 i

F = 6 F

- 8 \leq - \frac{3}{2} z + 1 \leq - 2

∣ x - 5 ∣ \leq - 4

12 x^{2} - 31 x + 7

4 x^{4} - 144 y^{4}

What are the solutions to the equation y^2-8y+25=0 ?
The solutions to the equation y^2-8y+25=0 are y=4+3i,y=4-3i
Find the zeros of y^2-8y+25=0
The zeros of y^2-8y+25=0 are y=4+3i,y=4-3i