What are the solutions to the equation 3x+10=x^2 ?

The solutions to the equation 3x+10=x^2 are x=5,x=-2

Find the zeros of 3x+10=x^2

The zeros of 3x+10=x^2 are x=5,x=-2

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3 x + 10 = x^{2}

x = 5, x = - 2

Solution steps

3 x + 10 = x^{2}

Switch sides

x^{2} = 3 x + 10

Move

10

to the left side

x^{2} - 10 = 3 x

Move

3 x

to the left side

x^{2} - 10 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

- 3 \cdot \frac{1}{5}

r^{2} + 8 r = 0

3 x^{2} - 2 x + 8 = 0

164883 (1 + \frac{45.26}{9.8})

\frac{1}{4} - \frac{1}{8}

What are the solutions to the equation 3x+10=x^2 ?
The solutions to the equation 3x+10=x^2 are x=5,x=-2
Find the zeros of 3x+10=x^2
The zeros of 3x+10=x^2 are x=5,x=-2