What are the solutions to the equation 4x^2+15x-54=0 ?

The solutions to the equation 4x^2+15x-54=0 are x= 9/4 ,x=-6

Find the zeros of 4x^2+15x-54=0

The zeros of 4x^2+15x-54=0 are x= 9/4 ,x=-6

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4 x^{2} + 15 x - 54 = 0

x = \frac{9}{4}, x = - 6

Decimal Notation

x = 2.25, x = - 6

Solution steps

4 x^{2} + 15 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 4 ( - 54 )}{2 \cdot 4}

1 5^{2} - 4 \cdot 4 (- 54) = 33

x_{1, 2} = \frac{- 15 \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 15 + 33}{2 \cdot 4}, x_{2} = \frac{- 15 - 33}{2 \cdot 4}

x = \frac{- 15 + 33}{2 \cdot 4} : \frac{9}{4}

x = \frac{- 15 - 33}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = \frac{9}{4}, x = - 6

- \frac{7}{3} - 1

2 x^{2} - 4 x - 30 = 0

\frac{4 r ^{4} s ^{5}}{24 r ^{4} s ^{- 5}}

5 x^{2} - 33 x + 18

3 + 5^{2}

What are the solutions to the equation 4x^2+15x-54=0 ?
The solutions to the equation 4x^2+15x-54=0 are x= 9/4 ,x=-6
Find the zeros of 4x^2+15x-54=0
The zeros of 4x^2+15x-54=0 are x= 9/4 ,x=-6