What is 5-3[2-4(x-2)]>= 6{2-[4-(x-3)]} ?

The solution to 5-3[2-4(x-2)]>= 6{2-[4-(x-3)]} is x>=-5/6

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5-3[2-4(x-2)]>= 6{2-[4-(x-3)]}

5 - 3 [2 - 4 (x - 2)] \geq 6 {2 - [4 - (x - 3)]}

x \geq - \frac{5}{6}

Interval Notation

[- \frac{5}{6}, \infty)

Decimal Notation

x \geq - 0.83333 \dots

Solution steps

5 - 3 [2 - 4 (x - 2)] \geq 6 {2 - [4 - (x - 3)]}

Rewrite in standard form

6 x + 5 \geq 0

Move

5

to the right side

6 x \geq - 5

Divide both sides by

6

x \geq - \frac{5}{6}

36 x^{2} + 25 = 60 x

x^{2} - 25 x

2 w + \frac{2}{3} (6 w - 12) = 4 w

- 3 x - 6 x = 6 + x - 7 x

- 2 x + 3 \geq 5

What is 5-3[2-4(x-2)]>= 6{2-[4-(x-3)]} ?
The solution to 5-3[2-4(x-2)]>= 6{2-[4-(x-3)]} is x>=-5/6