What is (2sqrt(2))/3 x-3<= (4sqrt(3))/2 ?

The solution to (2sqrt(2))/3 x-3<= (4sqrt(3))/2 is x<= (6sqrt(3)+9)/(2sqrt(2))

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(2sqrt(2))/3 x-3<= (4sqrt(3))/2

\frac{2 2}{3} x - 3 \leq \frac{4 3}{2}

x \leq \frac{6 3 + 9}{2 2}

Interval Notation

(- \infty, \frac{6 3 + 9}{2 2}]

Decimal Notation

x \leq 6.85621 \dots

Solution steps

\frac{2 2}{3} x - 3 \leq \frac{4 3}{2}

Divide the numbers:

\frac{4}{2} = 2

\frac{2 2}{3} x - 3 \leq 23

Move

3

to the right side

\frac{2 2}{3} x \leq 23 + 3

Multiply both sides by

3

22 x \leq 63 + 9

Divide both sides by

22

x \leq \frac{6 3 + 9}{2 2}

- 3 x^{2} + 4 x - 0.25 = 0

12 = x (240)^{2}

20 a - 21 = 18

e^{0.69314}

\frac{1}{2} + \frac{3}{2} - \frac{3}{2}

What is (2sqrt(2))/3 x-3<= (4sqrt(3))/2 ?
The solution to (2sqrt(2))/3 x-3<= (4sqrt(3))/2 is x<= (6sqrt(3)+9)/(2sqrt(2))