What is ((-3x^{-4}y)^{-4})/((5x^{-2)y^3)^0} ?

The solution to ((-3x^{-4}y)^{-4})/((5x^{-2)y^3)^0} is (x^{16})/(81y^4)

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simplify ((-3x^{-4}y)^{-4})/((5x^{-2)y^3)^0}

simplify

\frac{( - 3 x ^{- 4} y ) ^{- 4}}{( 5 x ^{- 2} y ^{3} ) ^{0}}

\frac{x ^{16}}{81 y ^{4}}

Solution steps

\frac{( - 3 x ^{- 4} y ) ^{- 4}}{( 5 x ^{- 2} y ^{3} ) ^{0}}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

(5 x^{- 2} y^{3})^{0} = 1

= \frac{( - 3 x ^{- 4} y ) ^{- 4}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= (- 3 x^{- 4} y)^{- 4}

Simplify

(- 3 x^{- 4} y)^{- 4} : \frac{x ^{16}}{81 y ^{4}}

= \frac{x ^{16}}{81 y ^{4}}

5 x^{2} - 10 x - 5

ln (5 x) + ln (3 x) > 9

2 x^{2} + 6 x = 1

2 x^{2} + x - 6 \geq 0

(\frac{4}{9})^{2}

What is ((-3x^{-4}y)^{-4})/((5x^{-2)y^3)^0} ?
The solution to ((-3x^{-4}y)^{-4})/((5x^{-2)y^3)^0} is (x^{16})/(81y^4)