What are the solutions to the equation (x^2)/(18)-x/9 =1 ?

The solutions to the equation (x^2)/(18)-x/9 =1 are x=1+sqrt(19),x=1-sqrt(19)

Find the zeros of (x^2)/(18)-x/9 =1

The zeros of (x^2)/(18)-x/9 =1 are x=1+sqrt(19),x=1-sqrt(19)

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\frac{x ^{2}}{18} - \frac{x}{9} = 1

x = 1 + 19, x = 1 - 19

Solution steps

\frac{x ^{2}}{18} - \frac{x}{9} = 1

Find Least Common Multiplier of

18, 9 : 18

Multiply by LCM=

18

\frac{x ^{2}}{18} \cdot 18 - \frac{x}{9} \cdot 18 = 1 \cdot 18

Simplify

x^{2} - 2 x = 18

Move

18

to the left side

x^{2} - 2 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 18) = 219

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 19}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 19}{2 \cdot 1} : 1 + 19

x = \frac{- ( - 2 ) - 2 19}{2 \cdot 1} : 1 - 19

The solutions to the quadratic equation are:

x = 1 + 19, x = 1 - 19

3 x + 12 = \frac{x + 7}{3}

i^{89}

16 x^{3} + 2 y^{3}

4 x^{3} y^{2} - 16 x^{2} y^{2} - 84 x y^{2}

18 + ∣ 2 x - 9 ∣ = 14

What are the solutions to the equation (x^2)/(18)-x/9 =1 ?
The solutions to the equation (x^2)/(18)-x/9 =1 are x=1+sqrt(19),x=1-sqrt(19)
Find the zeros of (x^2)/(18)-x/9 =1
The zeros of (x^2)/(18)-x/9 =1 are x=1+sqrt(19),x=1-sqrt(19)