What are the solutions to the equation 108=-16x^2-22+220 ?

The solutions to the equation 108=-16x^2-22+220 are x=(3sqrt(5))/(2sqrt(2)),x=-(3sqrt(5))/(2sqrt(2))

Find the zeros of 108=-16x^2-22+220

The zeros of 108=-16x^2-22+220 are x=(3sqrt(5))/(2sqrt(2)),x=-(3sqrt(5))/(2sqrt(2))

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108 = - 16 x^{2} - 22 + 220

x = \frac{3 5}{2 2}, x = - \frac{3 5}{2 2}

Decimal Notation

x = 2.37170 \dots, x = - 2.37170 \dots

Solution steps

108 = - 16 x^{2} - 22 + 220

Switch sides

- 16 x^{2} - 22 + 220 = 108

Move

22

to the right side

- 16 x^{2} + 220 = 130

Move

220

to the right side

- 16 x^{2} = - 90

Divide both sides by

- 16

x^{2} = \frac{45}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{45}{8}, x = - \frac{45}{8}

\frac{45}{8} = \frac{3 5}{2 2}

- \frac{45}{8} = - \frac{3 5}{2 2}

x = \frac{3 5}{2 2}, x = - \frac{3 5}{2 2}

2 a a^{2}

∣ 1 - 6 x ∣ - 11 < - 8

x (x - 2) < 0

\frac{∣ 7 - 6 x ∣}{∣ 6 x - 2 ∣} \geq 1

\frac{2}{3} + 2

What are the solutions to the equation 108=-16x^2-22+220 ?
The solutions to the equation 108=-16x^2-22+220 are x=(3sqrt(5))/(2sqrt(2)),x=-(3sqrt(5))/(2sqrt(2))
Find the zeros of 108=-16x^2-22+220
The zeros of 108=-16x^2-22+220 are x=(3sqrt(5))/(2sqrt(2)),x=-(3sqrt(5))/(2sqrt(2))