What is 6/(x-4)<= 3/(x-3) ?

The solution to 6/(x-4)<= 3/(x-3) is x<= 2\lor 3<x<4

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6/(x-4)<= 3/(x-3)

\frac{6}{x - 4} \leq \frac{3}{x - 3}

x \leq 2 or 3 < x < 4

Interval Notation

(- \infty, 2] \cup (3, 4)

Solution steps

\frac{6}{x - 4} \leq \frac{3}{x - 3}

Rewrite in standard form

\frac{3 x - 6}{( x - 4 ) ( x - 3 )} \leq 0

Factor

\frac{3 x - 6}{( x - 4 ) ( x - 3 )} : \frac{3 ( x - 2 )}{( x - 4 ) ( x - 3 )}

\frac{3 ( x - 2 )}{( x - 4 ) ( x - 3 )} \leq 0

Divide both sides by

3

\frac{\frac{3 ( x - 2 )}{( x - 4 ) ( x - 3 )}}{3} \leq \frac{0}{3}

Simplify

\frac{x - 2}{( x - 4 ) ( x - 3 )} \leq 0

Identify the intervals

x \leq 2 or 3 < x < 4

2 (12 - w) = - 2 (w - 17) - 10

\frac{b}{9} - 34 < - 36

10 \cdot 2

9 a^{2} - 8 a - 1

ln (\frac{1}{e})

What is 6/(x-4)<= 3/(x-3) ?
The solution to 6/(x-4)<= 3/(x-3) is x<= 2\lor 3<x<4