What are the solutions to the equation x^2+2x+3=0 ?

The solutions to the equation x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

Find the zeros of x^2+2x+3=0

The zeros of x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

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x^{2} + 2 x + 3 = 0

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

2 x^{2} + 17 x + 35

- 4 x^{2} + 4 x + 3

(x - 2) (x + 1) (2 x + 1) (x - 3) < 0

\frac{2}{i ^{15} - i ^{- 15}}

y + 3 = - y + 9

What are the solutions to the equation x^2+2x+3=0 ?
The solutions to the equation x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i
Find the zeros of x^2+2x+3=0
The zeros of x^2+2x+3=0 are x=-1+sqrt(2)i,x=-1-sqrt(2)i