What are the solutions to the equation 4x^2+16x+16=0 ?

The solutions to the equation 4x^2+16x+16=0 are x=-2

Find the zeros of 4x^2+16x+16=0

The zeros of 4x^2+16x+16=0 are x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 16 x + 16 = 0

x = - 2

Solution steps

4 x^{2} + 16 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 16}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 16 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 4}

x = \frac{- 16}{2 \cdot 4}

\frac{- 16}{2 \cdot 4} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

2 (t + 1) = 10

\frac{a}{( \frac{b}{c} )}

150

\frac{- 8 140}{2 5}

5 x^{2} - 2 x - 7 = 0

What are the solutions to the equation 4x^2+16x+16=0 ?
The solutions to the equation 4x^2+16x+16=0 are x=-2
Find the zeros of 4x^2+16x+16=0
The zeros of 4x^2+16x+16=0 are x=-2